Expert Answers

An illustration of the letter 'A' in a speech bubbles

You may also use the following method to factorize the quadratic expression, such that:

`2x^2 - 5x - 3  = 2(x - x_1)(x - x_2)`

`x_(1,2)` represent the solution to equation `2x^2 - 5x - 3 = 0`

You should use quadratic formula to evaluate `x_(1,2),` such that:

`x_(1,2) = (5+-sqrt(25 + 24))/4 => x_(1,2) = (5+-7)/4`

`x_1 = 3; x_2 = -1/2`

`2x^2 - 5x - 3 = 2(x - 3)(x - (-1/2))`

`2x^2 - 5x - 3 = (x - 3)(2x + 1)`

Hence, evaluating the factored form of quadratic expression, using the alternative method, yields `2x^2 - 5x - 3 = (x - 3)(2x + 1).`

Approved by eNotes Editorial Team
An illustration of the letter 'A' in a speech bubbles

`2x^2-5x-3`

`= 2x^2-6x+x-3`

`= 2x(x-3)+1(x-3)`

`= (x-3)(2x+1)`

So when you factorize `2x^2-5x-3 ` you will get;

`2x^2-5x-3= (x-3)(2x+1)`

Approved by eNotes Editorial Team
Soaring plane image

We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

  • 30,000+ book summaries
  • 20% study tools discount
  • Ad-free content
  • PDF downloads
  • 300,000+ answers
  • 5-star customer support
Start your 48-Hour Free Trial