Question

factor X^3+X^2-6Xno

Accepted Answer

factor X^3+X^2-6X
first factor X
==> x(x^2+x-6)
Now factor the equation (x^2+x-6)
==> x(x+3)(x-2)
If you need to obtain the eqution's roots, then you need to find x values in which the equation equals 0
==> x(x+3)(x+2)=0
==> x = 0, -3, and -2

Answer

To factor x^3+x^2-6x
Solution:
x^3+x^2-6x = x*x^2+x*x-x*6
Each term is a factor of x. So we can factor out x and rewite the given expression as:
x(x^2+x-6)...............(1)
The second factor x^2+x-6 in (1) by grouping the middle term   could be rewritten like:  x^2+3x-2x-6=
=x(x+3)-2(x+3)
=(x+3)(x-2). Substituting this for x^2+x-6 in (1), we get:
x(x+3)(x-2) which is the factored form of  x^3+x^2-6

Answer

So first take out the x so the equation looks like ax2+bx-c
Then you need to look at pairs of numbers that go into 6
2 x 3
6 x 1
Then you set up the equation as
x(x +/- _) (x+/- _)
so you see that before the second x the number is 1, meaning that when you add the two "_"'s together you need one. From this you can cross off 6 x 1 off your pairs and write
x(x+3) (x-2)
You can check this by adding the numbers together and getting positive one (the number needed) and multiplying and getting negative 6 (also the number needed)
Good luck!

Math

factor X^3+X^2-6X no

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