To factor x^3+x^2-6x

Solution:

x^3+x^2-6x = x*x^2+x*x-x*6

Each term is a factor of x. So we can factor out x and rewite the given expression as:

x(x^2+x-6)...............(1)

The second factor x^2+x-6 in (1) by grouping the middle term could be rewritten like: x^2+3x-2x-6=

=x(x+3)-2(x+3)

=(x+3)(x-2). Substituting this for x^2+x-6 in (1), we get:

x(x+3)(x-2) which is the factored form of x^3+x^2-6

So first take out the x so the equation looks like ax2+bx-c

Then you need to look at pairs of numbers that go into 6

2 x 3

6 x 1

Then you set up the equation as

x(x +/- _) (x+/- _)

so you see that before the second x the number is 1, meaning that when you add the two "_"'s together you need one. From this you can cross off 6 x 1 off your pairs and write

x(x+3) (x-2)

You can check this by adding the numbers together and getting positive one (the number needed) and multiplying and getting negative 6 (also the number needed)

Good luck!