`f(z) = 1/(z^2 + 1)` Find the derivative of the function.

Expert Answers
gsarora17 eNotes educator| Certified Educator

f(z)=`1/(z^2+1)`

`f'(z) = -1((z^2+1)^(-1-1))*2z`

`f'(z) = -1(z^2+1)^-2*2z`

`f'(z) = -(2z)/(z^2+1)^2`

goodthink | Student

Use a quotient rule:

`f'(z)=((0)(z^(2)+1)-(1)(2z))/((z^(2)+1))^(2) `

This simplifies to:

`f'(z)=(-2z)/(z^(2)+1)^(2) `