1 Answer | Add Yours
`f(x) = x/(x^2 + 1)`
`f'(x) = [(x^2 +1) - 2x*x]/(x^2 +1)^2`
`or, f'(x) = (x^2 + 1 - 2x^2)/(x^2 + 1)^2`
`or, f'(x) = (1-x^2)/(1+x^2)^2`
We’ve answered 318,916 questions. We can answer yours, too.Ask a question
We have a Math tutor online right now to help you!
To chat with a tutor, please set up a tutoring profile by creating an account and setting up a payment method. If you initiate a chat, please note you will be charged $0.50 a minute for tutoring time.