`f(x) = x/(x-1)`

`f'(x) = [(x-1) - x]/(x-1)^2`

`or, f'(x) = -1/(x-1)^2`

`f''(x) = 2/(x-1)^3`

`or, f''(x) = 2(x-1)^-3`

` `

More Math Questions »