`f(x) = x ln(x) - x` Differentiate the function.
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Luca B.
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You need to differentiate with respect to x, the given function, such that:
`f'(x) = (xln x - x)'`
`f'(x) = (xln x)' - x'`
You need to use the product rule to differentiate xln x, such that:
`(xln x)' = x'*ln x + x*(ln x)'`
`(xln x)' =1*ln x + x*(1/x)`
Reducing like terms, yields:
`(xln x)' = ln x + 1`
`f'(x) = ln x + 1 - 1`
Reducing like terms, yields:
`f'(x) = ln x`
Hence, evaluating the derivative of the function, yields `f'(x) = ln x.`
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