1 Answer | Add Yours
(a) The function has vertical asymptotes if it is reduced (no common factors in numerator and denominator) and the denominator is zero.
Thus `x^2-1=0 => x=+-1` . The vertical asymptotes are at x=-1 and x=1.
(b) The function is concave up on an interval where the 2nd derivative is positive.
`f''(x)>0` on (-1,0) and `(1,oo)` so the given function is concave up on (-1,0) and (1,19)
(3) The inflection point occurs when `f''(x)=0` and the sign of the second derivative changes parity.
The second derivative is zero at x=0 which is the inflection point.
We’ve answered 319,863 questions. We can answer yours, too.Ask a question