If  `f(x)= x^3-7x +6` is divisible by `x^2-3x + k` , then k = A. −2 B. 2 C. −3 D. 3

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jeew-m | College Teacher | (Level 1) Educator Emeritus

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It is given that `x^3-7x+6` is divisible by `x^2-3x+k` .

Therefore `x^2-3x+k` is a factor of` x^3-7x+6` . If the other factor is (x+p) we can say that;

`x^3-7x+6 = (x^2-3x+k)(x+p)`

`x^3-7x+6 = x^3+x^2(p-3)+x(k-3p)+kp`

By considering each coefficient;

`x^3rarr 1 = 1`

`x^2rarr 0 = p-3` hence `p = 3`

`x rarr -7 = k-3p` hence `k = -7+3p = -7+3xx3 = 2`

So the value of k = 2. The correct answer is at B.

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