`f(x) = x^3 - 3x + 2, [-2,2]` Verify that the function satisfies the hypotheses of the Mean Value Theorem on the given interval. Then find all numbers `c` that satisfy the conclusion of the Mean Value Theorem.
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The function is continuous on the closed interval [-2,2].
The function is differentiable on the open interval (-2,2).
The answers are `+-1.155` . Both c values are in the interval [-2,2].
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