`f(x) = x^2 - x - 2` Find the two x-intercepts of the function `f` and show that `f'(x) = 0` at some point between the two x-intercepts.

Expert Answers
Borys Shumyatskiy eNotes educator| Certified Educator

The x-intercepts are roots of f(x)=0. There are only two of those: -1 and 2.

The point between them where f'(x)=0 exists by Rolle's Theorem and we can find it:

f'(x)=2x-1, it is zero only at x=1/2.