`f(x) = (x^2)e^(-x)` (a) Use a graph of `f` to estimate the maximum and minimum values. Then find the exact values. (b) Estimate the value of `x` at which `f` increases most rapidly. Then find the exact value.
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a) Graph is attached . Minimum value of function is 0 at x=0
So the critical numbers can be evaluated for f'(x)=0
Critical numbers are x=0 , x=2
So the function has Minimum=0 at x=0
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