`f(x)=x^2+5x+6`

`g(x)=3x+1`

`(f(x))/(g(x)) = (x^2+5x+6)/(3x+1)`

This function `(f(x))/(g(x))` will be undefinable when `(3x+1)=0` OR `x = -1/3` .

For every other x there is no problem with `(f(x))/(g(x))` .

*So the domain of `(f(x))/(g(x))` is;*

*`x in R-[-1/3]` *

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