f(x) = (x^2 + 3x -2)^2   find f'(1)

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f(x) = (x^2 + 3x -2)^2

Let us calculate f'(x)

f'(x) = 2(x^2 + 3x -2) *(2x + 3)

       = (2x^2 + 6x -4 )(2x + 3)

f'(1) = (2 + 6 -4)(2 +3)

         = 4*5 = 20

==> f'(1) = 20

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