If f(x)=(x-1)^2 and g(x)=x^1/2 then gof=?

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We are given that f(x)=(x-1)^2 and g(x)=x^1/2. Now, to deterrmine the value for gof(x) we first have to find f(x) and substitute the result we get as the x value in g(x).

Now we know that f(x) = (x-1)^2

Also, g(x) = x^1/2

So g(f(x)) = g( (x-1)^2)

= [(x-1)^2)]^(1/2)

...

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We are given that f(x)=(x-1)^2 and g(x)=x^1/2. Now, to deterrmine the value for gof(x) we first have to find f(x) and substitute the result we get as the x value in g(x).

Now we know that f(x) = (x-1)^2

Also, g(x) = x^1/2

So g(f(x)) = g( (x-1)^2)

= [(x-1)^2)]^(1/2)

=(x-1)^(2/2)

=(x-1)

Therefore g(f(x)) = gof(x) = (x-1)

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