# `f(x) = sqrt(2)` Find the most general antiderivative of the function. (Check your answer by differentiation.)

*print*Print*list*Cite

Expert Answers

Borys Shumyatskiy | Certified Educator

The answer is `F(x) = x*sqrt(2) + C,` where C is any constant.

Let's check:

`F'(x) = (x*sqrt(2) + C)' = x'*sqrt(2) + 0 = 1*sqrt(2) = sqrt(2),` QED.