`f(x) = sin(x) - sqrt(3)cos(x)` Consider the function on the interval (0, 2pi). Apply first derivative test to identify all relative extrema.

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You need to find the relative extrema of the function, hence, you need to remember that the roots of the equation f'(x) = 0 are the extrema of the function.

You need to find the first derivative of the function:

`f'(x) = cos x + sqrt3*sin x`

You need to solve for x...

(The entire section contains 156 words.)

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