`f(x) = sin(x) - 1 , 0 < x < 2pi` Identify the open intervals on which the function is increasing or decreasing.

Textbook Question

Chapter 3, 3.3 - Problem 13 - Calculus of a Single Variable (10th Edition, Ron Larson).
See all solutions for this textbook.

1 Answer | Add Yours

embizze's profile pic

embizze | High School Teacher | (Level 1) Educator Emeritus

Posted on

Given f(x)=sin(x)-1:

A function is increasing on an interval if it is differentiable on the interval and the first derivative is positive; decreasing if the derivative is negative.

f'(x)=cos(x)

The cosine function is positive from (-pi/2,pi/2) with a period of 2pi.

---------------------------------------------------------------------------------------------

f(x)=sin(x)-1 is increasing on the open intervals (-pi/2 +/- 2npi,pi/2 +/- 2npi) where n is an integer.

f(x) is decreasing on (pi/2 +/- 2npi,3pi/2 +/- 2npi) for n an integer.

--------------------------------------------------------------------------------------------

The graph:

We’ve answered 318,911 questions. We can answer yours, too.

Ask a question