`f(x) = sin(x), [0,2pi]` Determine whether Rolle’s Theorem can be applied to `f` on the closed interval `[a, b]`. If Rolle’s Theorem can be applied, find all values of `c` in the open interval
Yes, it can. Function f is continuous on `[0, 2pi]` and is differentiable on` (0, 2pi)` . Also, `f(0) = f(2pi)` (both =0). There are all conditions of Rolle's Theorem.
Because of this there is at least one point c in `[0, 2pi]` such that f'(c)=0.
f'(x) = cos(x), it is zero at two points from `[0, 2pi]` : `pi/2` and `(3pi)/2` .