# `f(x) = sin(ln x)` Differentiate the function.

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You need to differentiate the function with respect to x, using the chain rule, such that:

`y' = (sin(ln x))'`

`y' = sin'(ln x)*(ln x)'*(x)'`

`y' =cos(ln x)*(1/x)*1`

`y' = (cos(ln x))/x`

**Hence, evaluating the derivative of the given function, yields `y' = (cos(ln x))/x.` **

**Differentiate the function.**

In order to differentiate this, we need to consider that there is an inner function inside sin(x).

This will require chain rule.

The derivative involving chain rule is:

Take the derivative.

`d f(x) /dx = cos(ln(x)) * (1/x)`

The answer is: `cos(ln(x))/x`