f(x) = sin2x + cosx

We need to find f(pi/2)

We will substitute with x= pi/2

==> f(pi/2) = sin(2*pi/2) + cos (pi/2)

= sin(pi) + cos(pi/2)

= 0 + 0 = 0

**Then the value of f(pi/2) = 0**

f(x) = sin2x + cosx

We need to find f(pi/2)

We will substitute with x= pi/2

==> f(pi/2) = sin(2*pi/2) + cos (pi/2)

= sin(pi) + cos(pi/2)

= 0 + 0 = 0

**Then the value of f(pi/2) = 0**