# `f(x) = sec(x)` Use the graph of the function to determine whether the function is even, odd, or neither. Verify your answer algebraically.

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Student Comments

loves2learn | Student

It is even.

`cos-x=cos(0-x) `

`cos(0-x)=sin0sinx+cos0cosx=cosx `

Therefore, `cos ` is even

`sec(-x)=1/cos-x `

This equals

`1/cosx=secx `

Therefore, `sec ` is even