`f(x) = sec(x)` Use the graph of the function to determine whether the function is even, odd, or neither. Verify your answer algebraically.

Textbook Question

Chapter 4, 4.6 - Problem 57 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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It is even.

 

`cos-x=cos(0-x) `

`cos(0-x)=sin0sinx+cos0cosx=cosx `

Therefore, `cos ` is even

`sec(-x)=1/cos-x `

This equals

`1/cosx=secx `

Therefore, `sec ` is even

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