We have the log to the base (15 - x)

f(x) = log(15-x) (x+5) = 2

=> (x + 5) = (15 - x)^2

=> x + 5 = 225 + x^2 - 30x

=> x^2 - 31x + 220 = 0

=> x^2 - 20 x - 11x + 220 =0

=> x( x - 20) - 11(x - 20) = 0

=> (x - 11)(x - 20) = 0

We get x = 11 and x = 20. Also, we can have logarithms with negative bases, so x can be 11 as well as 20.

Therefore the required values of **x are 11 and 20. **

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