`f(x) = kx^4, y = 4x - 1` Find k such that the line is tangent to the graph of the function.

Expert Answers
kalau eNotes educator| Certified Educator

The tangent line will touch one point of the original function.  This means that:

`kx^4 = 4x-1` 

We have two variables that we don't know.

Find the derivative of `f(x)` .  The k is a constant and we can use the power rule.

`f'(x) = 4kx^3`

The slope of the tangent line is four, so we will plug that into this equation.

`4 = 4kx^3`

Divide four k on both sides.


Substitute k back into the first equation, .

`(1/x^3)x^4 = 4x-1`

`x = 4x-1`


`x= 1/3`

Plug this back to to determine k.

`k(1/3)^4 = 4(1/3)-1`

`k(1/81)= 4/3-1`


Multiply 81 on both sides.

`k= 81/3 = 27`