f(x) = e^x ln(x^2+3). f'(x) f"(x)?

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You need to evaluate f'(x), hence, you need to differentiate the function f(x) with respect to x , using the product rule and the chain rule, such that:

`f'(x) = (e^x)'ln(x^2+3) + e^x (ln(x^2+3))' `

`f'(x) = e^x*ln(x^2+3) + e^x*1/(x^2+3)*(x^2+3)'`

`f'(x) = e^x*ln(x^2+3) +...

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