`f'''(x) = cos(x), f(0) = 1, f'(0) = 2, f''(0) = 3` Find `f`.
- print Print
- list Cite
Expert Answers
gsarora17
| Certified Educator
calendarEducator since 2015
write762 answers
starTop subjects are Math, Science, and Business
`f'''(x)=cos(x)`
`f''(x)=intcos(x)dx`
`f''(x)=sin(x)+C_1`
Now let's find C_1 , given f''(0)=3
`f''(0)=3=sin(0)+C_1`
`3=0+C_1`
`C_1=3`
`:.f''(x)=sin(x)+3`
(The entire section contains 88 words.)
Unlock This Answer Now
Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.
Related Questions
- f(x) = (x-3)/(x+1) find f'(0)f(x) = (x-3)/(x+1) find f'(0)
- 2 Educator Answers
- find f(x) given that f'''(x)=cos x, f(0)=8, f'(0)=4 and f''(0)=9.
- 1 Educator Answer
- Find the function f such that `f'(x) = f(x)(1-f(x))` and `f(0) = 1/2`
- 2 Educator Answers
- Solve the equation : 2*sin^2 x + cos x - 1 = 0
- 1 Educator Answer
- f(x)= x^2 / (x-2) find f'(1)
- 1 Educator Answer