`f'(x) = cos(x) - (1 - x^2)^(-1/2)` Find `f`.

Textbook Question

Chapter 4, Review - Problem 65 - Calculus: Early Transcendentals (7th Edition, James Stewart).
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hkj1385 | (Level 1) Assistant Educator

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`f'(x) = cos(x) - (1-x^2)^(-1/2)`

`f(x) = sin(x) - sin^-1(x) + c`

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