`f''(x) = 8x^3 + 5, f(1) = 0, f'(1) = 8` Find `f`.

Textbook Question

Chapter 4, 4.9 - Problem 40 - Calculus: Early Transcendentals (7th Edition, James Stewart).
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gsarora17's profile pic

gsarora17 | (Level 2) Associate Educator

Posted on





Now let's find constant c_1 , given f'(1)=8







Now let's find constant c_2 , given f(1)=0





scisser's profile pic

scisser | (Level 3) Honors

Posted on

Find the anti derivatives and solve for the constants.


`f'(1)=8` , therefore,



Thus, `f'(x)=2x^4+5x+1`

Do the same thing again


Plug in the point` f(1)=0`





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