To find the solution of the differential equation `f'(x)=6x`
` ` with initial condition `f(0)=8 ` , integrate both sides:
`int(f'(x) dx)=int(6x dx) =>f(x)+c_1=3x^2+c_2` ,where `c_1,c_2 ` are constants. This means that `f(x)=3x^2+c_2-c_1=>f(x)=3x^2+c ` . Using the initial condition `f(0)=3(0)^2+c=8=>c=8=>f(x)=3x^2+8 ` . Below we have plotted the differential equation and the solution.
First, find the integral
Solve for the constant using the given point `f(0)=8`