`f(x) = 5 - x^2, (3, -4)` Find the slope of the tangent line to the graph of the function at the given point.
hkj1385 | Certified Educator
The given function is:-
f(x) = 5 - (x^2)
differentiating both sides w.r.t 'x' we get
f'(x) = 0 - 2x
Now, slope of the tangent at the point (3,-4) = f'(3) = - 2*3 = -6