`f(x) = 5 - x^2, (3, -4)` Find the slope of the tangent line to the graph of the function at the given point.

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Chapter 2, 2.1 - Problem 8 - Calculus of a Single Variable (10th Edition, Ron Larson).
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hkj1385 | (Level 1) Assistant Educator

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The given function is:-

f(x) = 5 - (x^2)

differentiating both sides w.r.t 'x' we get

f'(x) = 0 - 2x

Now, slope of the tangent at the point (3,-4) = f'(3) = - 2*3  = -6

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