`f(x) = 5 - x^2, (3, -4)` Find the slope of the tangent line to the graph of the function at the given point.

Expert Answers
hkj1385 eNotes educator| Certified Educator

The given function is:-

f(x) = 5 - (x^2)

differentiating both sides w.r.t 'x' we get

f'(x) = 0 - 2x

Now, slope of the tangent at the point (3,-4) = f'(3) = - 2*3  = -6