Note:- If x = x^n ; where n = constant ; then dy/dx = n*x^(n-1)
`f(x) = 4x^(3/2)`
`f'(x) = 4*(3/2)*x^(1/2)`
`or, f'(x) = 6*x^(1/2)`
`f''(x) = 6*(1/2)*x^(-1/2)`
`or, f''(x) = 3*x^(-1/2)`
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