`f(x) = -3x^2 - 4x - 2` Find the critical numbers, open intervals on which the function is increasing or decreasing, apply first derivative test to identify all relative extrema.
Find the critical values for x by setting the first derivative of the function equal to zero and solving for the x value(s).
The critical value for the first derivative is x=-2/3.
If f'(x)>0, the function is increasing in the interval.
If f'(x)<0, the function is decreasing in the interval.
Choose a value for x that is less than -2/3.
f'(-1)=2 Since f'(-1)>0 the graph of the function is increasing in the interval
Choose a value for x that is greater than -2/3.
f'(0)=-4 Since f'(0)<0 the graph of the function is decreasing in the interval
Because the direction of the function changed from increasing to decreasing a relative maximum will exist at x=-2/3. The relative maximum is the point (-2/3, -2/3).