`f(x) = 2x^3 - 6x, [0,3]` Find the absolute extrema of the function on the closed interval.

Expert Answers
mathace eNotes educator| Certified Educator

Given: `f(x)=2x^3-6x,[0, 3]`

Find the critical values for x by setting the derivative equal to zero and solving for the x value(s).




`x=-1, x=1`

The critical values for x are x=1 and x=-1. Plug in the critical value(s) and the endpoints of the interval into f(x). Because x=-1 is not in the interval [0, 3], it is not necessary to plug in the x=-1





Examine the f(x) values to determine the absolute extrema

The absolute minimum value is the point (1, -4).

The absolute maximum value is the point (3, 36).

sciencesolve eNotes educator| Certified Educator

You need to find the absolute extrema of the function, hence, you need to differentiate the function with respect to x, such that:

`f'(x) = (2x^3 - 6x)'`

`f'(x) = 6x^2 - 6`

You need to solve for x the equation f'(x) = 0, such that:

`6x^2 - 6 = 0`

6`(x^2 - 1) = 0 => x^2 - 1 = 0 => (x - 1)(x + 1) = 0 => x = 1` and `x = -1`

You need to notice that only `x = 1 in [0,3]`

Hence, evaluating the absolute extrema of the function, in interval [0,3], yields x= 1.