`f(x) = 2x^2 - 3x + 1, [0,2]` Verify that the function satisfies the hypotheses of the Mean Value Theorem on the given interval. Then find all numbers `c` that satisfy the conclusion of the Mean Value Theorem.
The function is a continuous polynomial on the closed interval [0,2].
The function is differentiable on the open interval (0,2).
The answer is c=1 which is in the interval [0,2].