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The inverse function of `f(x) = (2x+1)/(x+2)` has to be determined.
`y = f(x) = (2x+1)/(x+2)`
=> `xy + 2y = 2x + 1`
=> `xy - 2x = 1 - 2y`
=> `x(y - 2) = (1 - 2y)`
=> `x = (1 - 2y)/(y - 2)`
interchange x and y
=> `y = (1 - 2x)/(x - 2)`
The inverse function is `f^-1(x) = (1 - 2x)/(x - 2)`
The graph of `f(x)` and `f^-1(x)` are:
The equation of the line on which the common points lie is y = x.
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