`f(x) = (2x)/(1 + x^2)^2, [0, 2]` Find the average value of the function on the given interval.

Expert Answers

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Given `f(x)=(2x)/(1+x^2)^2, [0, 2]`

Average Value Formula=`1/(b-a)int_a^bf(x)dx`





Integrate using the u-subsitution method.

Let `u=1+x^2`















The average value is 2/5.


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