`f(x) = 2sin(x) + sin(2x), [0, 2pi]` Find the points of inflection and discuss the concavity of the graph of the function.
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Eric Bizzell
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Given f(x)=2sin(x)+sin(2x) on the interval [0,2pi], find the points of inflection and discuss the concavity:
Find the second derivative:
f'(x)=2cos(x)+2cos(2x)
f''(x)=-2sin(x)-4sin(2x)
Inflection points occur when the second derivative is zero (and changes sign.)
-2sinx-4sin(2x)=0
-8sin(x)cos(x)-2sin(x)=0 Using the...
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