`f(x) = 2sin(x) + cos(2x), [0, 2pi]` Find all relative extrema, use the second derivative test where applicable.

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Given the function f(x)=2sinx+cos(2x)  in the interval `[0,2pi]`

Taking the first derivative we get,


Inorder to find the critical points we have to equate f'(x)=0.

So we get,


i.e. cosx-2sinxcosx=0



(The entire section contains 147 words.)

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