`f(x) = 27/(x^3), (3,1)` Find the slope of the graph of the functions at the given point.
hkj1385 | Certified Educator
Note:- 1) If y = x^n ; where n = constant ; then dy/dx = n*x^(n-1)
`f(x) = 27/x^3`
`f'(x) = -81/x^4`
``Now, slope of the graph = f'(x)
Hence slope at (3,1) = f'(3) = `-81/3^4`
`or, f'(3) = -81/81 = -1`