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Take the derivative of the given function. The chain rule will be shown in the steps. The derivative of the inner function (x-4) with the respect to x is 1.
`f'(x) =2 * 2(x-4)^(2-1) * (1)`
`f'(x) =4(x-4) = 4x-16`
Substitute the x value of the given point to find the slope at that point.
`f'(2) = 4(2)-16`
The answer is:
`f'(2) = -8`
We can graph the derivative function to show that we have a slope of negative eight at x=2.
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