`f(x) = 2 sin(x) - sin(2x), [0, pi]` Find the average value of the function on the given interval.

Expert Answers

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The average value on an interval is the integral on this interval divided by the length of the interval.

The length is `pi` . The integral is

`(-2cos(x)+1/2 cos(2x))|_0^pi=2+1/2+2-1/2=4.`

So the average value is `4/pi.`

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