`f(x) = 2/(root(3)(x)) + 3cos(x)` Find the derivative of the function.
The first term is the same as:
Take the derivative of this term.
`-1/3(2)x^(-1/3-1) = -2/3x^(-4/3)`
The derivative of `3cos(x)` is `-3sin(x)` .
Combine the terms.
Rewrite the first term to eliminate the negative exponent.
The answer is: