`f(theta) = 2sec(theta) + tan(theta), 0 < theta < 2pi` Find the critical numbers of the function.

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Given the function f(x) =2sec(`theta)`+tan(`theta)` in the interval 0<theta<2 pi

We have to find the critical points.

So let us first take the derivative of the function and evaluate it to zero.





implies, theta= 7pi/6 and 11pi/6  (that comes in the interval 0<theta<2 pi)

These are the critical points.


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