You need to find the critical points of the function, hence, you need to evaluate the solutions to the equation `f'(theta) = 0` .
You need to evaluate the first derivative:
`f'(theta) = -2 sin theta + 2sin theta*cos theta`
You need to solve for theta `f'(theta) = 0` , such that:
`-2 sin theta + 2sin theta*cos theta= 0 `
Factoring out `2sin theta` yields:
`2sin theta*(-1 + cos theta) = 0`
Put `2sin theta = 0 => sin theta = 0`
`theta = (-1)^k*arcsin 0 + kpi`
`theta = kpi`
Put `-1 + cos theta= 0 =>cos theta = 1`
`theta = +-arccos 1 + 2kpi`
`theta = 2kpi`
Hence, evaluating the critical numbers of the function for `f'(theta) = 0` , yields `theta =2kpi, theta = kpi.`
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