# `f(t) = sin(e^t) + e^sin(t)` Find the derivative of the function.

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### 2 Answers

Note:- 1) If y = sin(at) ; then dy/dx = a*cos(at)

2) If y = e^(at) ; then dy/dx = a*e^(at); where a = constant

Now,

f(t) = sin(e^t) + e^(sint)

f(t) is in the form of u + v ; where u = sin(e^t) & v = e^(sint)

Thus, by the addtion rule of differentiation;

f'(t) = u' + v'

Now, u = sin(e^t)

thus, u' = (e^t)*cos(e^t)........(1)

Also, v = e^(sint)

Thus, v' = cost*e^(sint).......(2)

Hence, f'(x) = u' + v' = [(e^t)*cos(e^t)] + [cost*e^(sint)]

`f(t)=sin(e^t)+e^(sint)`

`f'(t)=cos(e^t).e^t+e^(sint).cost`