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`f(t) = root(3)(8 - t), [0, 8]` Find the absolute maximum and minimum values of f on the given interval

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`f(t)=root(3)(8-t)`

differentiating,

`f'(t)=(1/3)(8-t)^(1/3-1)(-1)`

`f'(t)=-1/(3(8-t)^(2/3))`

Now to find the absolute extrema of the function , that is continuous on a closed interval, we have to find the critical numbers that are in the interval and evaluate the...

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