`f(t) = root(3)(8 - t), [0, 8]` Find the absolute maximum and minimum values of f on the given interval
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gsarora17
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`f(t)=root(3)(8-t)`
differentiating,
`f'(t)=(1/3)(8-t)^(1/3-1)(-1)`
`f'(t)=-1/(3(8-t)^(2/3))`
Now to find the absolute extrema of the function , that is continuous on a closed interval, we have to find the critical numbers that are in the interval and evaluate the...
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