`f(t) = 3t - t^2, (0, 0)` Find the slope of the tangent line to the graph of the function at the given point.
hkj1385 | Certified Educator
The given function is:-
f(t) = 3t - (t^2)
differentiating both sides w.r.t 't' we get
f'(t) = 3 - 2t
Now, slope of the tangent at the point (0,0) = f'(0) = 3 - (2*0) = 3