`f(t) = 3t - t^2, (0, 0)` Find the slope of the tangent line to the graph of the function at the given point.

Expert Answers

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The given function is:-

f(t) = 3t - (t^2)

differentiating both sides w.r.t 't' we get

f'(t) = 3 - 2t

Now, slope of the tangent at the point (0,0) = f'(0) = 3 - (2*0) = 3

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