`f(t) = 2cos(t) + sin(2t), [0, pi/2]` Find the absolute maximum and minimum values of f on the given interval

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The function has absolute minimum=0 at x=`pi/2`

`f(t)=2cos(t)+sin(2t)`

differentiating,

`f'(t)=-2sint+2cos(2t)` 

Now to find the absolute extrema of the function , that is continuous on a closed interval, we have to find the critical numbers that are in the interval and evaluate the function at the endpoints and...

(The entire section contains 2 answers and 181 words.)

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