The domain of f is (0,oo) therefore there are no holes in the domain.

**At x= 0.**

`lim_(x rarr 0)f(x)=2+lim_(x arr 0)ln(x)/x=-oo`

Since the limit is infinite **there is a vertical asymptote at x=0**

**When** `x rarr oo`

**Recall:** if `lim_(x rarr oo) (f(x))/x=a` and `lim_(x rarr oo) f(x)-ax=b`

then y=ax+b is an oblique asymptote.

In our case, `(f(x))/x=(-x+2+(ln(x))/x)/x=-1+2/x+ln(x)/(x^2)`

`lim_(x rarr oo) (ln x)/(x^2)=0`

Therefore` lim_(x rarr oo) (f(x))/x=-1+0+0` (a=-1)

`f(x)-(-x)=2+ln(x)/x`

` lim_(x rarr oo) f(x)-(-x)=2+lim_(x rarr oo) ln(x)/x=2` (b=2)

y=-x+2** is a oblique asymptote.**

**Conclusion 2 asymptotes: vertical asymptote x=0 and oblique asymptote y=-x+2**

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