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Given two consecutive numbers.
Then we can assume that the first number is x.
Then the other number will be x+1.
We are given that the sum of the numbers is 15.
Then, we can write as follow:
x + ( x+ 1) = 15
==> x + x + 1 = 15
==> 2x + 1 = 15
Now we will subtract 1 from both sides.
==> 2x = 14
Now we will divide by 2.
==> x = 7
Then the first number is 7, and the other number is 8.
Then, 7 and 8 are two consecutive numbers whose sum is 15.
The answer is that the numbers are 7 and 8. You can find this mathematically.
You know that they are consecutive so if the first number is x then the next number is x + 1. So you could have the following equations:
x + y = 15
y = x + 1
x + X + 1 = 15
2x = 14
x = 7
y = 8
If the integers are consecutive, that means that one is odd and the other is even.
We'll put the numbers as a and a+1.
Their sum is 15:
a + a + 1 = 15
We'll combine like terms:
2a = 15 - 1
2a = 14
a = 7
The next integer number is a + 1 = 7 + 1 = 8
The consecutive integer numbers are: 7 and 8.
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